What is ##x## in this equation: ##(x+6)/5 = 9/5 – 2(x-3)##?

##x=3##

To|solve ##(x+6)/5=9/5-2(x-3)##, let us multiply each side by ##5## and we get

##(x+6)/5×5=9/5×5-2(x-3)×5##

= ##x+6=9-10(x-3)##

= ##x+6=9-10x+30##

Now moving terms containing ##x## to left and constant terms to right, we get

##x+10x=9+30-6##

or ##11x=33##

or ##x=33/11=3##