How do you solve ##y=x-4##, ##2y=-x+10## by graphing and classify the system?

The (shared points) point of intersection is at ##(x,y)->(6,2)##.

The system is of type: first order simultaneous equation system

For each equation: Select at least 2 values for ##x## and substitute into the equations to determine the corresponding values of y. Draw a line through each point extending it to the edge of the squares on the graph paper.

##color(blue)(“Label all your points and put a title on your graph. Gives you extra”)## ##color(blue)(“marks for good communication.”)##

Equation 1 ##y=x-4##

Equation 2 ##2y=-x+10″ “color(red)(vec(“divide both sides by 2″))” ” y=-x/2+5## ‘~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ The system is a first order simultaneous equation system

Note: ##x->”first order”## ##x^2->”second order”## ##x^3->”third order”##

Solution: The (shared points) point of intersection is at ##(x,y)->(6,2)##. The system is a first order simultaneous equation system

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