How do you solve the system ## y=6x – 11## and ##-2 – 3y = -7## by substitution?

Given ##”[1] “y=6x-11## ##”[2] “-2-3y = -7##

from ##”[1]”## we can substitute ##6x-11## for ##y## in ##”[2]”## ##”[3] “-2-3(6x-11) = -7##

##”[4] ” -3(6x-11) = -5##

##”[5] ” 6x-11 = 5/3##

##”[6] ” 6x = 38/3##

##”[7] ” x = 19/9##

Note that ##”[2]”## can be solved directly for ##y## ##”[8] “-3y = -5##

##”[9] ” y = 5/3##

Query: Was the second equation intended to be ##-2x-3y = -7##?