How do you solve ##4times 8*2^{2}##?

##4xx8*2^2=128##

We can use PEMDAS, we should first start with Parentheses (none here), then , Multiplication, Division, Addition and Subtraction (last three too are not applicable here).

Hence ##4xx8*2^2##

= ##4xx8*4##

= ##4xx32##

= ##128##