algebra…..

1.  

Use the quadratic formula to solve the equation.

–x2 + 6x – 5 = 0  (1 point)

  • –5, –1
  • 1, 5
  • –5, 11
  • 2, 10

  2.  

A landscaper is designing a flower garden in the shape of a trapezoid. She wants the shorter base to be 3 yards greater than the height and the longer base to be 7 yards greater than the height. She wants the area to be 295 square yards. The situation is modeled by the equation h2 + 5h = 295. Use the quadratic formula to find the height that will give the desired area. Round to the nearest hundredth of a yard.  (1 point)

  • 17.36 yards
  • 600 yards
  • 14.86 yards
  • 29.71 yards

  3.  

What is the number of real solutions?

12×2 – 11x = 11  (1 point)

  • two real solutions
  • one real solution
  • cannot be determined
  • no real solutions

  4.  

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the machine recommends that the temperature of the machine part remain below 141°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by  T = –0.005×2 + 0.45x + 125.  Will the temperature of the part ever reach or exceed 141°F? Use the discriminant of a quadratic equation to decide.  (1 point)

  • yes
  • no