A parallel-plate capacitor has a capacitance of 1.35 pF. If a 12.0 V battery is connected to this capacitor, how much electrical potential energy would it store?

##E_p=9.72*10^13J##

##c=1.35″ ” p F=1.35*10^12 F##

##V=12V##

##E_p=1/2*C*V^2##

##E_p=1/2*1.35*10^12*12^2##

##E_p=1/2*1.35*10^12*144##

##E_p=72*1.35*10^12##

##E_p=97.2*10^12##

##E_p=9.72*10^13J##